[Solved]LinearLayout (in xml) to LinearLayout(in code)

Rebirthing · by **Rebirthing** » Fri Dec 21, 2007 8:16 am

Syntax: [ Download ] [ Hide ]

Using xml Syntax Highlighting

<?xml version="1.0" encoding="utf-8"?>
 
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
 
              android:orientation="horizontal"
 
              android:layout_width="wrap_content"
 
              android:layout_height="wrap_content">
 
   <ImageView id="@+id/icon" 
 
                         android:layout_width="wrap_content"  
 
             android:layout_height="wrap_content" 
 
             android:layout_weight="0"            
 
             android:paddingTop="2px"
 
             android:paddingRight="5px"/>
 
   <TextView id="@+id/text"
 
             android:layout_width="wrap_content"  
 
             android:layout_height="wrap_content"/>         
 
</LinearLayout>
Parsed in 0.002 seconds,  using GeSHi 1.0.8.4

I want to create instance of LinearLayout that matchs with XML.

Rebirthing · by **Rebirthing** » Fri Dec 21, 2007 9:20 am

ViewInflate is key?..

reading document..

plusminus · by **plusminus** » Fri Dec 21, 2007 4:41 pm

Hello Rebirthing,

you want the above transformed into Java-Code :?:

Regards,
plusminus

Rebirthing · by **Rebirthing** » Sat Dec 22, 2007 1:41 am

I mean how to create instance of predesc xml resources.

I found the way to make it.

It's ViewInflate that make instance from xml.

thx

plusminus · by **plusminus** » Sat Dec 22, 2007 5:22 pm

Hello Rebirthing,

please post your code, so other can benefit from it

Regards,
plusminus

[Solved]LinearLayout (in xml) to LinearLayout(in code)

[Solved]LinearLayout (in xml) to LinearLayout(in code)

perhaps...

not exactly..

Who is online