Hello

i am creating one quiz application, for question page i have created one view by using Linear layout in that i have added four TextAreas, first TextArea for question and reaming three are for answer cell. so now, when user select the answer cell i want to show next question screen for that i am thinking of creating new view. means some questions may have two answers so i want to create that run time.

how to create new view at run time and how to switch for new view.

Hi,

For ur requirement , u can use a single linear layout and add child views to it whenever u need a new View.

Say for example ,



When u have formed a new LinearLayout as the next View , it can be added as the child to the parent .

Now,



You can remove the previous View that u had added to the parent first by calling



because after the new child was added , the previous view would have now become the second (index = 1 ) child.

You can apply the above logic whenever u have to display a new View.

Regards,
Satish

Thanks for reply

i think u replied my each and every post

thanks once again.

Now I want to explain you in detail what i am trying to do

I have created one question screen by using Linear Layout

like this




I have used text view for displaying Question and Answers

What I Want ?

when user click on Answers A

the current view will replaced with new view with new question and answer.

the new view contains any number of answers like 2 or 5

like this



in short

i want to switch the new view when user clicks on answer.(with animation but this is not important)

I have used view Animator but am not able to create dynamic child for view animator

because for view animator we have to define all child's in XML layout and i don't want to use any XML dependency.

please help me !!!!!!

satishkumar_lskin wrote:Hi,

For ur requirement , u can use a single linear layout and add child views to it whenever u need a new View.

Say for example ,

Syntax: [ Download ] [ Hide ]

Syntax: [ Download ] [ Show ]

Using java Syntax Highlighting

1. LinearLayout parent = new LinearLayout ( context );
2. parent.setLayoutParams(width, height ); //width, height can be set as needed.
3. parent.addView(myView , 0 );

Parsed in 0.040 seconds, using GeSHi 1.0.8.4

When u have formed a new LinearLayout as the next View , it can be added as the child to the parent .

Now,

Syntax: [ Download ] [ Hide ]

Syntax: [ Download ] [ Show ]

Using java Syntax Highlighting

1. parent.addView(newLinearLayout, 0 );

Parsed in 0.037 seconds, using GeSHi 1.0.8.4

You can remove the previous View that u had added to the parent first by calling

Syntax: [ Download ] [ Hide ]

Syntax: [ Download ] [ Show ]

Using java Syntax Highlighting

1. parent.removeViewAt(1);

Parsed in 0.035 seconds, using GeSHi 1.0.8.4

because after the new child was added , the previous view would have now become the second (index = 1 ) child.

You can apply the above logic whenever u have to display a new View.

Regards,
Satish

Hi,
How about using this method



in ViewAnimator class ?.

ViewAnimator class extends FrameLayout , which means that the lastly added child view will be displayed on top of others. So after displaying the initial view , use the above addView() method to display the new child View.

The new child View can be constructed as a dynamic LinearLayout. Have a factory method which will produce a new Vertical LinearLayout if u pass it an ArrayList containing the views (textViews, for example ) to be added to it.

U can remove the initial view by finding the appropriate API for it in the ViewAnimator docs.

Repeat the above logic whenever u need a new View to be shown.