Upload Files to Web Server

raquibulbari · by **raquibulbari** » Thu Jan 24, 2008 5:34 pm

Here is the code that worked for me

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FileInputStream fileInputStream = null;
 
    void thirdTry(){
 
        String exsistingFileName = "asdf.png";
 
        String lineEnd = "\r\n";
 
        String twoHyphens = "--";
 
        String boundary = "*****";
 
        String Tag="3rd";
 
        try
 
        {
 
        //------------------ CLIENT REQUEST
 
        Log.e(Tag,"Inside second Method");
 
        // Open a HTTP connection to the URL
 
       //connectURL is a URL object
 
        HttpURLConnection conn = (HttpURLConnection) connectURL.openConnection();
 
        // Allow Inputs
 
        conn.setDoInput(true);
 
        // Allow Outputs
 
        conn.setDoOutput(true);
 
        // Don't use a cached copy.
 
        conn.setUseCaches(false);
 
        // Use a post method.
 
        conn.setRequestMethod("POST");
 
        conn.setRequestProperty("Connection", "Keep-Alive");
 
        conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);
 
        DataOutputStream dos = new DataOutputStream( conn.getOutputStream() );
 
        dos.writeBytes(twoHyphens + boundary + lineEnd);
 
        dos.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + exsistingFileName +"\"" + lineEnd);
 
        dos.writeBytes(lineEnd);
 
        Log.e(Tag,"Headers are written");
 
        // create a buffer of maximum size
 
        int bytesAvailable = fileInputStream.available();
 
        int maxBufferSize = 1024;
 
        int bufferSize = Math.min(bytesAvailable, maxBufferSize);
 
        byte[] buffer = new byte[bufferSize];
 
        // read file and write it into form...
 
        int bytesRead = fileInputStream.read(buffer, 0, bufferSize);
 
        while (bytesRead > 0)
 
        {
 
                dos.write(buffer, 0, bufferSize);
 
                bytesAvailable = fileInputStream.available();
 
                bufferSize = Math.min(bytesAvailable, maxBufferSize);
 
                bytesRead = fileInputStream.read(buffer, 0, bufferSize);
 
        }
 
        // send multipart form data necesssary after file data...
 
        dos.writeBytes(lineEnd);
 
        dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
 
        // close streams
 
        Log.e(Tag,"File is written");
 
        fileInputStream.close();
 
        dos.flush();
 
        InputStream is = conn.getInputStream();
 
                //      retrieve the response from server
 
                int ch;
 
                StringBuffer b =new StringBuffer();
 
                while( ( ch = is.read() ) != -1 ){
 
                        b.append( (char)ch );
 
        }
 
                String s=b.toString();          
 
                Log.i("Fuck response",s);
 
        dos.close();
 
        }
 
        catch (MalformedURLException ex)
 
        {
 
        Log.e(Tag, "error: " + ex.getMessage(), ex);
 
        }
 
        catch (IOException ioe)
 
        {
 
        Log.e(Tag, "error: " + ioe.getMessage(), ioe);
 
        }
 
    }
 
Parsed in 0.181 seconds,  using GeSHi 1.0.8.4

This code worked for me, php code is same as posted before

Katharnavas · by **Katharnavas** » Fri Jan 25, 2008 5:03 am

raquibulbari wrote:Katharnavas thanks man , your code came in great help for me, the whole day i was trying to upload image, the code was about to be same like you , at least your code worked, thanks man, i was just getting frustrated on me

Its nice to hear that you got ur problem fixed..

cyberrob · by **cyberrob** » Mon Feb 04, 2008 7:48 am

Hey guys, I try codes you post above, Seems everything ok but...

I got a Java.io.FileNotFoundException

I try

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String exsistingFileName = "ning";
 
fileInputStream = openFileInput(exsistingFileName);
Parsed in 0.130 seconds,  using GeSHi 1.0.8.4

exception happened at line2, the one I assign path to fileInputStream
Same result when I use

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fileInputStream = new FileInputStream(new File(exsistingFileName))
Parsed in 0.144 seconds,  using GeSHi 1.0.8.4

So I'm wondering where should I point the file path to ??
I put the .png file in /res/drawble/
and include it by using getString(R.drawable.abc.png),which also give me the same exception.

Hope someone could help me out here! THX a LOT!

plusminus · by **plusminus** » Mon Feb 04, 2008 10:22 am

Hello cyberrob,

:idea:

raquibulbari probably had the file manually pushed to the emulator :!:

you cannot use getString(R.drawable.abc.png);, because it is only capable of grabbing String-Resources and not the Names of other resources. Also you can not access images you placed under "/res/drawable/xyz.png", by their filenames, because they got compiled into your application.

Regards,
plusminus

cyberrob · by **cyberrob** » Tue Feb 12, 2008 3:33 am

Oh!that's why I cant do it that way,ok! I try manually push file into it. Thanks!

plusminus wrote:Hello cyberrob,

raquibulbari probably had the file manually pushed to the emulator
you cannot use getString(R.drawable.abc.png);, because it is only capable of grabbing String-Resources and not the Names of other resources. Also you can not access images you placed under "/res/drawable/xyz.png", by their filenames, because they got compiled into your application.

Regards,
plusminus

cyberrob · by **cyberrob** » Thu Feb 14, 2008 9:10 am

Finally I got everything WORK!!
I found posts above miss to assign FileInputStream a value, so I assign the file I wanna upload like this:

Code: Select all: fileInputStream = new FileInputStream(exsistingFileName);

in try-catch block, so it all work out! :lol:

Next Step try to show the php echo msg on "showalert"
Thank you guys!!

plusminus wrote:Hello cyberrob,

raquibulbari probably had the file manually pushed to the emulator
you cannot use getString(R.drawable.abc.png);, because it is only capable of grabbing String-Resources and not the Names of other resources. Also you can not access images you placed under "/res/drawable/xyz.png", by their filenames, because they got compiled into your application.

Regards,
plusminus

inter · by **inter** » Wed Feb 27, 2008 3:17 pm

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<?php
 
$target_path = "./ploads/";
 
$target_path = $target_path . basename( $_FILES['uploadedfile']['name']);
 
if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) {
 
    echo "The file ".  basename( $_FILES['uploadedfile']['name']).
 
    " has been uploaded";
 
} else{
 
    echo "There was an error uploading the file, please try again!";
 
}
 
?>
Parsed in 0.272 seconds,  using GeSHi 1.0.8.4

I use this code in server side .But it not work .It response "There was an error uploading the side ,please try again!!"

The client side is same above.
Can you help me. Thanks.

inter · by **inter** » Wed Feb 27, 2008 3:26 pm

I'm sory .I have just done it
Thank a lot!!!!

ekambresh · by **ekambresh** » Mon Mar 17, 2008 11:31 am

please tell me wre to plce the image file while uploading to the server....if possible send me the tutorial

tnx
ekambresh

venkat · by **venkat** » Mon Mar 17, 2008 2:39 pm

Hi ekambresh, u can upload images also. please push images manually to files folder using "DDMS" tool .

here how you can push images into "files" folder.

window --> show view --> File Explorer than, navigate to data/data/[your package structre]/files then,

select that folder, then , there is two small phone icons. first one is used to pull files from that folder to your system and another one is used to push files into that folder.

use second icon to push files from your system to "files" folder.

I hope it will help.

rohan · by **rohan** » Wed Mar 19, 2008 2:35 pm

venkat wrote:Hi ekambresh, u can upload images also. please push images manually to files folder using "DDMS" tool .

here how you can push images into "files" folder.

window --> show view --> File Explorer than, navigate to data/data/[your package structre]/files then,

select that folder, then , there is two small phone icons. first one is used to pull files from that folder to your system and another one is used to push files into that folder.

use second icon to push files from your system to "files" folder.

I hope it will help.

hi venkat,
I am new to android.
I did not get the path that you have given "window --> show view --> File Explorer than, navigate to data/data/[your package structre]/files" . how do I go to the above path? and also what is "DDMS" tool .

thanx in advance

mehta · by **mehta** » Sun Mar 30, 2008 1:45 am

In the examples above, the path of the file to be uploaded is hardcoded. Is there a way to let the user choose the file path dynamically?

marielisacr · by **marielisacr** » Mon Jul 14, 2008 2:18 pm

Hi, am trying to upoad a file to a server,

the problem is that I need to send two differents parameters to the server, one is the file and the another is a text.

I am trying this code:

public void doFileUpload(String exsistingFileName, String xml){

HttpURLConnection conn = null;
DataOutputStream dos = null;
DataInputStream inStream = null;

//String exsistingFileName = "/sdcard/img2.jpg";
// Is this the place are you doing something wrong.

String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "-----------------------------29772313742745";

int bytesRead, bytesAvailable, bufferSize;

byte[] buffer;

int maxBufferSize = 1*1024*1024;

String responseFromServer = "";

String urlString = Constants.WEB_ADDRESS+"upload.do";

try
{
//------------------ CLIENT REQUEST

Log.e("MediaPlayer","Inside second Method");

FileInputStream fileInputStream = new FileInputStream(new File(exsistingFileName) );

// open a URL connection to the Servlet

URL url = new URL(urlString);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
// Allow Inputs
conn.setDoInput(true);
// Allow Outputs
conn.setDoOutput(true);
// Don't use a cached copy.
conn.setUseCaches(false);
// Use a post method.
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("Cookie", "JSESSIONID="+PlayList.getSessionId());
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);

dos = new DataOutputStream( conn.getOutputStream() );

dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"xml\""+lineEnd+URLEncoder.encode(xml,"UTF-8") + lineEnd);
dos.writeBytes(boundary + lineEnd);
//dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"fileFile\";filename=\"" + exsistingFileName +"\"" + lineEnd);
dos.writeBytes(lineEnd);

Log.e("MediaPlayer","xml ");

Log.e("MediaPlayer","Headers are written");

// create a buffer of maximum size

bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];

// read file and write it into form...

bytesRead = fileInputStream.read(buffer, 0, bufferSize);

while (bytesRead > 0)
{
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}

// send multipart form data necesssary after file data...

dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);

// close streams
Log.e("MediaPlayer","File is written");
fileInputStream.close();
dos.flush();
dos.close();

}
catch (MalformedURLException ex)
{
Log.e("MediaPlayer", "error: " + ex.getMessage(), ex);
}

catch (Exception ioe)
{
Log.e("MediaPlayer", "error: " + ioe.getMessage(), ioe);
}

//------------------ read the SERVER RESPONSE

try {
inStream = new DataInputStream ( conn.getInputStream() );
String str;

while (( str = inStream.readLine()) != null)
{
Log.e("MediaPlayer","Server Response"+str);
}
inStream.close();

}
catch (Exception ioex){
Log.e("MediaPlayer", "error: " + ioex.getMessage(), ioex);
}

}

but it doesn't work, it only recognizes one of the parameters. I got an error on the server's side that the file is null and the text variable had everything, including the file.

I hope someone can help me.

Thanks.

marielisacr · by **marielisacr** » Mon Jul 14, 2008 2:20 pm

Sorry, here is the code more clear

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public void doFileUpload(String exsistingFileName, String xml){
 
                HttpURLConnection conn = null;
 
                DataOutputStream dos = null;
 
                DataInputStream inStream = null;
 
                //String exsistingFileName = "/sdcard/img2.jpg"; 
 
                // Is this the place are you doing something wrong.
 
                String lineEnd = "\r\n";
 
                String twoHyphens = "--";
 
                String boundary =  "-----------------------------29772313742745";
 
                int bytesRead, bytesAvailable, bufferSize;
 
                byte[] buffer;
 
                int maxBufferSize = 1*1024*1024;
 
                String responseFromServer = "";
 
                String urlString = Constants.WEB_ADDRESS+"upload.do";
 
                try
 
                {
 
                        //------------------ CLIENT REQUEST
 
                        Log.e("MediaPlayer","Inside second Method");
 
                        FileInputStream fileInputStream = new FileInputStream(new File(exsistingFileName) );
 
                        // open a URL connection to the Servlet
 
                        URL url = new URL(urlString);
 
                        // Open a HTTP connection to the URL
 
                        conn = (HttpURLConnection) url.openConnection();
 
                        // Allow Inputs
 
                        conn.setDoInput(true);
 
                        // Allow Outputs
 
                        conn.setDoOutput(true);
 
                        // Don't use a cached copy.
 
                        conn.setUseCaches(false);
 
                        // Use a post method.
 
                        conn.setRequestMethod("POST");
 
                        conn.setRequestProperty("Connection", "Keep-Alive");
 
                        conn.setRequestProperty("Cookie", "JSESSIONID="+PlayList.getSessionId());
 
                        conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);
 
                        dos = new DataOutputStream( conn.getOutputStream() );
 
                        dos.writeBytes(twoHyphens + boundary + lineEnd);
 
                        dos.writeBytes("Content-Disposition: form-data; name=\"xml\""+lineEnd+URLEncoder.encode(xml,"UTF-8") + lineEnd);
 
                        dos.writeBytes(boundary + lineEnd);
 
                        //dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
 
                        dos.writeBytes("Content-Disposition: form-data; name=\"fileFile\";filename=\"" + exsistingFileName +"\"" + lineEnd);
 
                        dos.writeBytes(lineEnd); 
 
                        Log.e("MediaPlayer","xml ");
 
                        Log.e("MediaPlayer","Headers are written");
 
                        // create a buffer of maximum size
 
                        bytesAvailable = fileInputStream.available();
 
                        bufferSize = Math.min(bytesAvailable, maxBufferSize);
 
                        buffer = new byte[bufferSize];
 
                        // read file and write it into form...
 
                        bytesRead = fileInputStream.read(buffer, 0, bufferSize);
 
                        while (bytesRead > 0)
 
                        {
 
                                dos.write(buffer, 0, bufferSize);
 
                                bytesAvailable = fileInputStream.available();
 
                                bufferSize = Math.min(bytesAvailable, maxBufferSize);
 
                                bytesRead = fileInputStream.read(buffer, 0, bufferSize);
 
                        }
 
                        // send multipart form data necesssary after file data...
 
                        dos.writeBytes(lineEnd);
 
                        dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
 
                        // close streams
 
                        Log.e("MediaPlayer","File is written");
 
                        fileInputStream.close();
 
                        dos.flush();
 
                        dos.close();
 
                }
 
                catch (MalformedURLException ex)
 
                {
 
                        Log.e("MediaPlayer", "error: " + ex.getMessage(), ex);
 
                }
 
                catch (Exception ioe)
 
                {
 
                        Log.e("MediaPlayer", "error: " + ioe.getMessage(), ioe);
 
                }
 
                //------------------ read the SERVER RESPONSE
 
                try {
 
                        inStream = new DataInputStream ( conn.getInputStream() );
 
                        String str;
 
                        while (( str = inStream.readLine()) != null)
 
                        {
 
                                Log.e("MediaPlayer","Server Response"+str);
 
                        }
 
                        inStream.close();
 
                }
 
                catch (Exception ioex){
 
                        Log.e("MediaPlayer", "error: " + ioex.getMessage(), ioex);
 
                }
 
        }
Parsed in 0.391 seconds,  using GeSHi 1.0.8.4

Niketa · by **Niketa** » Tue Oct 07, 2008 12:30 pm

hi,

Can any one tell what if the server is the java.

Actually i want to retrieve file in a servlet so what should i do.

I mean to say if i want to send data in servlet then how can i get it. I have success fully send data to server but

how can i retrieve it at server in java code.

Thank you

Upload Files to Web Server

wre to place image file,while uploding to server

path

how to get Data to server in java

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