Special URI order by android?

Jimmy Malibu · by **Jimmy Malibu** » Tue Aug 05, 2008 3:23 pm

Hallo!
Has got android a special URI order to list a URI?
When my code is reading in a javaprogram I get a String back.
When my code is reading in android then I get nothing no failure, too.
I have debuggt my code and the problem was the order
"URL url = new URL( "http://localhost:8046/IListServices" );
is = url.openStream();"
Know anyone my problem?

Hier my code:

Syntax: [ Download ] [ Hide ]

Using java Syntax Highlighting

 
import java.io.IOException;
 
import java.io.InputStream;
 
import java.net.HttpURLConnection;
 
import java.net.URL;
 
import java.util.Scanner;
 
class ReadAllFromUrl
 
{
 
        String name;
 
        String kurzN;
 
        String version;
 
    public void url(){ 
 
         InputStream is = null;
 
    try
 
    {
 
      URL url = new URL( "http://localhost:8046/IListServices" );
 
      is = url.openStream();
 
      Scanner scanner = new Scanner(is);
 
      String[] splittArray;
 
           splittArray = scanner.next().split(" ");
 
                name = splittArray[0]; //await the first String from splittArray
 
    }
 
    catch ( Exception e ) {
 
      e.printStackTrace();
 
    }
 
    finally {
 
      if ( is != null )
 
        try { is.close(); } catch ( IOException e ) { e.printStackTrace(); }
 
    }
 
  }
 
}
 
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cgreen · by **cgreen** » Wed Aug 06, 2008 9:12 am

This is because localhost points to your android emulator, and not your webservice, which is probably located on your computer. Think of the emulator as an independent device.

You'll have to insert the numerical IP-Address of the computer, which hosts the webservice. ( e.g.: 192.168.2.123 )

Jimmy Malibu · by **Jimmy Malibu** » Thu Aug 07, 2008 12:07 pm

Thanks for your help, it was the right solution for my problem.

Special URI order by android?

Special URI order by android?

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