Hello,

I have three activities.

I need the activityOne to be the default (The one that launches first)

activityTwo and activityThree are launched by activityOne

When I deploy the app to a device I see three apps showing. I assume this is because there are three activities. I only want one app showing and the activityOne launching when its selected.

Any ideas?


<activity android:name=".activityOne"
android:label="@string/app_name">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>

<activity android:name=".activityTwo" android:label="@string/app_name">
</activity>
<activity android:name=".activityThree" android:label="@string/app_name">
</activity>

Just to confirm,

I have a app with three screens (views) should I create an activity for each one?

Thanks

Yes, you should create an activitiy for every view.

For your manifest.xml:
1. Use the '.xml' Tags when posting
2. There is an "</activity>" Tag missing (".activityOne" isnt closed)

Thanks for the replies. Its working now

Noob question, how do you call each of the activities? I've tried listeners and onClicks but end up with a forced close.

For example, I'm trying to get from "inputDate" to "inputTime" activities with a "next" button. I comment out each line and find it "blows up" at the Button statement.

Thanks for your guidance.

public class inputDate extends Activity {

@Override
public void onCreate(Bundle savedValues) {
super.onCreate(savedValues);
setContentView(R.layout.input_date);
Button cmd_submit = (Button) findViewById(R.id.next);
cmd_submit.setOnClickListener(new OnClickListener() {
public void onClick(View arg0) {
Intent inty = new Intent();
inty.setClass(inputDate.this, inputTime.class);
startActivity(inty);
}
});
}
}