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anddev.org • View topic - How to write value on XML file in Android?

How to write value on XML file in Android?

Tutorials with advanced 'difficulty' and more Lines of Code.

How to write value on XML file in Android?

Postby Virtue » Fri Nov 28, 2008 10:14 am

Hi all,
I want to write some values on XML file to save application configuration.
I have to use method?

Thanks in advance.
Virtue. :)
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How to Create XML File through Android Program?

Postby prajkti.khadse » Tue Jul 14, 2009 7:27 am

Hi Virtue
Me too want to Create/Write XML file to store My Application Settings.
Did you get any Solution for?

Regards,
Prajkti
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Postby Shone » Wed Jul 15, 2009 3:49 pm

There is a package javax.xml.parsers in the SDK which supports XML parsing and writing.
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xml parsing from folder

Postby myster23 » Thu Jul 16, 2009 10:33 am

Can a xml file be parsed from a folder from an Android project? if yes which folder is that?
I want to parse the following tags from a folder:
<Data>
<Question1>Do you like C++</Question1>
<Option1>Yes</Option1>
<Option2>No</Option2>
</Data>
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Postby Shone » Thu Jul 16, 2009 11:06 am

You can put it into the /res folder in your Android project.
@see http://developer.android.com/guide/topi ... -i18n.html
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Postby TheSmile » Sun Jul 19, 2009 11:57 pm

Hi Virtue,

according to this link here http://developer.android.com/guide/topi ... orage.html you can use SharedPreferences to store app configuration. It's an easy way to do it. It's a map with key - value pairs that will be created.
Whatever comes ... just keep on smiling :)

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convert

Postby myster23 » Wed Jul 22, 2009 8:11 am

The question is this:
How can I convert an InputStream instrem to InputSource ;

For example, is the following allowed ?

InputSource in = new InputSource();
InputStream instrem;
instrem=Resources.getSystem().openRawResource(R.raw.questions);
in=instrem;

or

How can I convert an InputSource instrem to File ;

For example, is the following allowed ?

File rd;
InputStream instrem;
instrem=Resources.getSystem().openRawResource(R.raw.questions);
rd=instrem;

What can I do so that this can be allowed ?
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Postby TheSmile » Wed Jul 22, 2009 9:17 am

Hi myster23.

looks like you have more of a java problam rather then an android problem.
I don't know if this line of code

Code: Select all
instrem=Resources.getSystem().openRawResource(R.raw.questions);


is correct, but if it is, you can just create a new InputSource and pass the InputStream as a parameter into the constructor.
Have a look at the java docs here:
http://java.sun.com/j2se/1.4.2/docs/api ... ource.html
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Postby myster23 » Tue Aug 04, 2009 7:01 am

The following program shows: error: Resource ID #0x7f040000
What is the problem? How can I fix it?

ParseRes.java--->

Code: Select all
try {
TextView tx1=new TextView(this);
TextView tvx=new TextView(this);
        XmlResourceParser xpp=Resources.getSystem().getXml(R.xml.myxml);
       
        int eventType=xpp.getEventType();
          eventType=xpp.nextTag();
       while(eventType!=XmlResourceParser.END_DOCUMENT)
      {    
         if(xpp.getName().equals("name"))
         {   
            tx1.setText("YES!");
         }
         else { tx1.setText("NO!");  }
          
        eventType=xpp.nextTag();
      }
     this.setContentView(tx1);
   }catch (Exception e) {
      // TODO Auto-generated catch block
   tvx.setText("Error: " + e.getMessage( ));
        Log.e(MY_DEBUG_TAG, "WeatherQueryError", e);
      this.setContentView(tvx);
   }



R.java--->

package com.android.Parsing;

Code: Select all
public final class R {
    public static final class attr {
    }
    public static final class drawable {
        public static final int icon=0x7f020000;
    }
    public static final class layout {
        public static final int main=0x7f030000;
    }
    public static final class string {
        public static final int app_name=0x7f050001;
        public static final int hello=0x7f050000;
    }
    public static final class xml {
        public static final int myxml=0x7f040000;
    }
}


The xml file I parse is this:
myxml.xml--->

Code: Select all
<?xml version="1.0" encoding="utf-8" ?>
<Person>
<name>Bill</name>
<last>Gates</last>
</Person>
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Postby TheSmile » Tue Aug 04, 2009 9:44 am

Hi,

I haven't testet your code but just having a look at your post here you changed your code from your last post.

You wrote:
Code: Select all
XmlResourceParser xpp=Resources.getSystem().getXml(R.xml.myxml);


You need to load raw data (your xml) with this method:
Code: Select all
openRawResource(int id) from the Resource class 


Second, if you would read the docs (sorry to says that but is's obvious) you cannot use
Code: Select all
Resources.getSystem()
for your application because it returns the system resources and NOT the application resources.

You need to have a look at the API-docs for the Resource class here.
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Postby myster23 » Wed Aug 05, 2009 7:05 am

Firstly, I changed the XmlResourceParser xpp=Resources.getSystem().getXml(R.xml.myxml)
to XmlResourceParser xpp=getResources().getXml(R.xml.myxml) but it shows the
Error: Binary XML file line#-1:expected start or end tag (position:Binary XML file line #-1)

What does it mean ?

Secondly, the getResources().openRawResources(R.raw.myxml) returns an InputStream that is,
InputStream inp=getResources().openRawResource(R.raw.myxml). How can I read the inp ?
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xml parsing

Postby hPushpa18 » Fri Nov 06, 2009 6:07 am

Hi,

Are you able to extract the data from xml now?If yes, can u plz attach your project(entire source code) and send it to me.I also need to do xmlparsing.Its really urgetn.Plz help

Thanks and Regards,
Pushpa
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